The match statement

match value: followed by case pattern: blocks compares the value against each pattern in order and runs the first that fits. case "saturday" | "sunday": matches either string; case _: is the catch-all. It is Python 3.10 and newer, and it reads better than a long elif chain when you are testing one value against fixed options.

Patterns can also capture and destructure (case [x, y]: or case {"type": t}:), but the fixed-values form is the one you will use most. Normalize the input first, for example with .lower(), so "Saturday" and "saturday" match the same case.

def http_text(code):
    match code:
        case 200:
            return "OK"
        case 404:
            return "Not found"
        case _:
            return "Something else"

Your task

Write day_type(day) that returns "weekend" for saturday or sunday, "weekday" for the other five days, and "unknown" for anything else. It should not care about capital letters.

def day_type(day):
    match day.lower():
        case "saturday" | "sunday":
            return "weekend"
        case "monday" | "tuesday" | "wednesday" | "thursday" | "friday":
            return "weekday"
        case _:
            return "unknown"